I hope your job does not require you to be able to calculate squares quickly. Mine doesn't. But in case it does, here is a little trick for relatively small numbers.
First thing is to memorize squares upto 25. Schools generally hammer these into your brain, so that's a reasonable requirement I guess.
Suppose the number is between 25 and 50. Let's express it as 25+n, 25>n>0. Get the square of 25-n (now that you remember it). Take it and add 100n. Voila.
Let's take an example. Suppose you want to square 43.
43=25+n, n=18
25-18=7 whose square is 49. add 100n=18*100=1800 to it.
Answer is 1849.
Next step. Suppose the number lies between 50 and 100. Let's say 73.
73=50+n, n=23
So let's first find square of 50-n=27.
27 lies between 0 and 50 so you can use the trick mentioned above to find it if necessay.
Anyway it is 729.
Add to that 200n=4600. So 4600+729=5329, the required answer.
Note here we multiplied by 200 (as 'base' is 50, not 25), rest is same.
You can go on for x=100+n but then the amount of backtracking takes a little longer. And you have to multiply by 400.
The explanation of why this works is pretty simple, but it will be lengthy (in fact I started this post with it, but it just kept growing, and not to mention blogger is terrible with formatting), so I'll skip it.
First thing is to memorize squares upto 25. Schools generally hammer these into your brain, so that's a reasonable requirement I guess.
Suppose the number is between 25 and 50. Let's express it as 25+n, 25>n>0. Get the square of 25-n (now that you remember it). Take it and add 100n. Voila.
Let's take an example. Suppose you want to square 43.
43=25+n, n=18
25-18=7 whose square is 49. add 100n=18*100=1800 to it.
Answer is 1849.
Next step. Suppose the number lies between 50 and 100. Let's say 73.
73=50+n, n=23
So let's first find square of 50-n=27.
27 lies between 0 and 50 so you can use the trick mentioned above to find it if necessay.
Anyway it is 729.
Add to that 200n=4600. So 4600+729=5329, the required answer.
Note here we multiplied by 200 (as 'base' is 50, not 25), rest is same.
You can go on for x=100+n but then the amount of backtracking takes a little longer. And you have to multiply by 400.
The explanation of why this works is pretty simple, but it will be lengthy (in fact I started this post with it, but it just kept growing, and not to mention blogger is terrible with formatting), so I'll skip it.
2 comments:
I'll need a calculator :D
Me too :p
Post a Comment